The "=" command prints the current line number to standard output. One way to find out the line numbers that contain a pattern is to use:

# add line numbers first,# then use grep,# then just print the number
cat -n file | grep 'PATTERN' | awk '{print $1}'

The?sed?solution is:

sed -n '/PATTERN/ =' file

Earlier I used the following to find the number of lines in a file

#!/bin/sh
lines=`wc -l file | awk '{print $1}' `

Using the "=" command can simplify this:

#!/bin/sh
lines=`sed -n '$=' file `

The "=" command only accepts one address,so if you want to print the number for a range of lines,you must use the curly braces:

#!/bin/sh
# Just print the line numbers 
sed -n '/begin/,/end/ {
=
d
}' file

Since the "=" command only prints to standard output,you cannot print the line number on the same line as the pattern. You need to edit multi-line patterns to do this.

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